## GR0877 Problem 97

**PROBLEM STATEMENT**: *This problem is still being typed*.

**SOLUTION**: (**E**) According to Compton scattering formula, the difference in wavelength of the scattered and incident photon is , where is the scattering angle. In our case, and . But , so , where is the energy of the scattered photon. Thus, , from which .

*Found a typo? Comment!*

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2 small typos: you wrote that but should be .

Another typo is in the compton scattering formula: should be rather than

Thanks! Both typos have been fixed.

For those that don’t remember (or know anything about) the Compton formula, you can solve with conservation laws. Momentum of the electron will be equal to \(E^2+E_F^2\) (conservation of momentum). Plug into \(E+m=E_f+\sqrt{m^2+p_e^2}\) to get the final answer.

Surely the easiasiasiest way is consider and extreme panorama where

$\lim_{m \to +\infty} E’ = E$

cuz the photon shouldn’t lose its energy due to the momentum conservation (it’s an elastic scattering).

E is the only answer that fits this prediction.

OH…IT’S CALLED thomson scattering!

Surely the easiasiasiest way is consider and extreme panorama where

\[ \lim_{m \to +\infty} E’ = E \]

cuz the photon shouldn’t lose its energy due to the momentum conservation (it’s an elastic scattering).

E is the only answer that fits this prediction.