GR0877 Problem 92
PROBLEM STATEMENT: This problem is still being typed.
SOLUTION: (E) According to Ampere’s law , where is the total current enclosed by the integration path: , is the current density. For the enclosed current is zero, so . For the enclosed current is and from Ampere’s law , so which shows a linear character with respect to on . For the enclosed current is and or . The only graph that reflects such a behavior of is (E).
Found a typo? Comment!
Jump to the problem
Want to get a full PDF with solutions? Read THIS.
The comments appending particular solutions are due to the respective users. Educational Testing Service, ETS, the ETS logo, Graduate Record Examinations, and GRE are registered trademarks of Educational Testing Service. The examination questions are © 2008 by ETS.