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## GR0877 Problem 80

PROBLEM STATEMENT: This problem is still being typed.

SOLUTION: (C) Clearly, $\displaystyle \nu_0 = \frac{1}{2 \pi} \sqrt{\frac{k}{m_0}}$, $\displaystyle \nu = \frac{1}{2 \pi} \sqrt{\frac{2k}{m}}$, where $\nu_0 = 1$ Hz, $m_0 = 1$ kg, $m = 8$ kg. Thus, $\displaystyle \nu = \nu_0 \sqrt{\frac{2m_0}{m}} = 1 \cdot \sqrt{\frac{2 \cdot 1}{8}} = 1/2$ (Hz).

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