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## GR0877 Problem 78

PROBLEM STATEMENT: This problem is still being typed.

SOLUTION: (B) According to the Gibb’s distribution $\displaystyle P_i = \frac{1}{Z} \exp \left(-\frac{E_i}{kT}\right)$, where $\displaystyle Z = \sum_i \exp \left( -\frac{E_i}{kT}\right)$. Thus, $\displaystyle P_2 = \frac{\exp \left( -\frac{E_2}{kT}\right)}{\exp \left( -\frac{E_1}{kT}\right) + \exp \left( -\frac{E_2}{kT}\right)}$.

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