Home > 0877 > GR0877 Problem 60

GR0877 Problem 60

PROBLEM STATEMENT: This problem is still being typed.

SOLUTION: (C) Take a point $(x, 0, 0)$ on the $x$-axis. At this point the magnetic field due to the wire along $\hat{\mathbf{z}}$ is $\mu_0 I/(2 \pi x)$; due to the wire crossing the first and third quadrants is $\displaystyle \frac{\mu_0 I}{2 \pi x \sin{45^{\circ}}}$; due to the wire crossing the second and fourth quadrants is $\displaystyle \frac{\mu_0 I}{2 \pi x \sin{45^{\circ}}}$. Thus, the net magnetic field at point $(x, 0, 0)$ is $\displaystyle \frac{\mu_0 I}{2 \pi x } (1 + 2 \sqrt{2})$.

Found a typo? Comment!