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## GR0877 Problem 57

PROBLEM STATEMENT: This problem is still being typed.

SOLUTION: (B) For both figures accelerations of masses $2m$ and $m$ are the same and can be calculated via Newton’s second law for the whole system of two bodies: $3ma = F$, $a = F/(3m)$. For the first figure $ma = F_{12}$ and $F_{12} = F/3$. For the second figure $2ma = F_{12}$ and $F_{12} = 2F/3$. Thus, choice (B).

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