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## GR0877 Problem 55

PROBLEM STATEMENT: This problem is still being typed.

SOLUTION: (A) Applying relativistic Doppler effect formula: $\displaystyle \frac{\lambda_0}{\lambda_{lab}} = \sqrt{\frac{1+\beta}{1-\beta}} \approx \frac{4}{3}$. Thus, $16-16\beta = 9 + 9 \beta$ $\implies$ $\beta = 7/25 = 0.28$.

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1. 07.11.2012 at 07:16

I must be getting something wrong, but according to wikipedia (http://en.wikipedia.org/wiki/Relativistic_Doppler_effect) the lambda terms in the doppler equation are actually reciprocal of what is presented on this page. My textbook also seems to be showing them the other way around. Weird.

2. 10.11.2012 at 05:36

I got it. My bad. Never mind! Thanks.

3. 12.03.2013 at 04:18

I used delta_lamba/lamba_0 = v/c to get 1/3 c which is close enough to 0.28.