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GR0877 Problem 52

PROBLEM STATEMENT: This problem is still being typed.

SOLUTION: (C) According to Bragg’s law $2d \sin {\theta} = n \lambda$, where $\theta$ is the angle between incident ray and scattering planes. In our case $n = 1$ and $\displaystyle d = \frac{\lambda}{2 \sin{\theta}} \approx 2 \lambda = 0.500$ (nm).

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