Home > 0877 > GR0877 Problem 33

## GR0877 Problem 33

PROBLEM STATEMENT: This problem is still being typed.

SOLUTION: (E) According to the first law of thermodynamics $dS = \frac{1}{T}dU + \frac{P}{T} dV = mc \frac{dT}{T} + \nu R \frac{dV}{V}$, where $c$ is the specific heat (per one kilogram). Assuming water is incompressible fluid one has $dS = mc \frac{dT}{T}$. Integrating this from $T_1$ to $T_2$ one obtain $mc \ln{\frac{T_2}{T_1}}$.

Found a typo? Comment!

 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100

Want to get a full PDF with solutions? Read THIS.

The comments appending particular solutions are due to the respective users. Educational Testing Service, ETS, the ETS logo, Graduate Record Examinations, and GRE are registered trademarks of Educational Testing Service. The examination questions are © 2008 by ETS.