Home > 0877 > GR0877 Problem 32

GR0877 Problem 32

PROBLEM STATEMENT: This problem is still being typed.

SOLUTION: (A) Who says Bernoulli’s principle is unlikely on the PGRE? According to this principle, one has P_0 + \frac{\rho v_0^2}{2} = P + \frac{\rho v^2}{2} (there is no \rho g z term here because of horizontality of the pipe). Conservation of mass gives: \rho v_0 S = \rho v S \implies v=4v_0, since S = \pi r^2 = (\pi r_0^2)/4 = S_0/4. Plugging v = 4 v_0 into the first equation one finally obtain P = P_0 + \frac{\rho v_0^2}{2} - 16 \frac{\rho v_0^2}{2} = P_0 - \frac{15}{2} \rho v_0^2.

Found a typo? Comment!

Jump to the problem

1 2 3 4 5 6 7 8 9 10
11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30
31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50
51 52 53 54 55 56 57 58 59 60
61 62 63 64 65 66 67 68 69 70
71 72 73 74 75 76 77 78 79 80
81 82 83 84 85 86 87 88 89 90
91 92 93 94 95 96 97 98 99 100

Want to get a full PDF with solutions? Read THIS.

The comments appending particular solutions are due to the respective users. Educational Testing Service, ETS, the ETS logo, Graduate Record Examinations, and GRE are registered trademarks of Educational Testing Service. The examination questions are © 2008 by ETS.

Categories: 0877 Tags: , , , ,
  1. No comments yet.
  1. No trackbacks yet.

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s

%d bloggers like this: